math
posted by b6 .
2x^3+4x^23x^26x when x=3
I did2(3)^3+4(3)^23(3)^26(3)
2(27)+4(9)3(9)6(3)
54+362718
902718
6318
45
is this correct?
Thanks

looks good to me.
might have saved some work by combining 4x^23x^2 to be just x^2 before evaluating
or, you could have factored it a bit:
2x^2(x+2)  3x(x+2) = x(2x3)(x+2)
= 3(3)(5) = 45
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