A 25 mF capacitor is connected to a source of potential difference 100V. What is the resulting charge in the capacitor?
To find the resulting charge in the capacitor, we can use the formula:
Q = C * V
Where:
Q is the charge
C is the capacitance
V is the potential difference (voltage)
Given that the capacitance is 25 mF (millifarads) and the potential difference is 100V, we can substitute these values into the formula:
Q = (25 * 10^-3 F) * 100V
Calculating this equation, we get:
Q = 2.5 C
Therefore, the resulting charge in the capacitor is 2.5 coulombs (C).
To find the charge stored in a capacitor, we can use the formula:
Q = C * V,
where Q is the charge, C is the capacitance, and V is the potential difference.
In this case, the capacitance (C) is given as 25 mF (millifarads) and the potential difference (V) is 100V. However, we need to convert the capacitance from millifarads to farads since the SI unit for capacitance is farads.
1 farad (F) = 1000 millifarads (mF)
So, converting the given capacitance:
C = 25 mF = 25 * (1/1000) F = 0.025 F
Now, we can substitute the values into the formula:
Q = 0.025 F * 100V
Q = 2.5 coulombs
Therefore, the resulting charge stored in the capacitor is 2.5 coulombs.
C=q/U
q= CU
u=0.5*qv
u=0.5*25*100
u=1250