Can someone please help me out here?
I've tried several times and i keep getting the wrong answer :( lol
A small crucible is filled with 100.00 mL of n-hexadecane (MW (226.44 g/mol), density (0.7703 g/mL))
and 2.10 L of 7-octenyltrichlorosilane (MW (245.65 g/mol), density (1.07 g/mL)).
Calculate the concentration in mM of the reagent in solution
Number of moles of n-hexadane is
100 mL * (0.7703 g/mL) * (1 mol / 226.44 g)
mL and g units cancel
= 100 * (0.7703/226.44) moles n-hexadane
The total volume of the final solution is 100 mL + 2100 mL = 2200 mL = 2.2 L
The concentration of n-hexadane in mM is
100 * (0.7703/226.44) M / 2.2L * (1000 mM / M)
If n-hexadane is your reagent, then this is the final answer; otherwise repeat this type of calculation to find the final concentration of 7-ocenyltrichlorosilane in solution.
To calculate the concentration in mM (millimolar) of the reagent in the solution, follow these steps:
Step 1: Calculate the moles of each compound.
1.1 For n-hexadecane (C16H34):
- First, calculate the grams of n-hexadecane using the density and volume given:
Mass = density x volume = 0.7703 g/mL x 100.00 mL = 77.03 g
- Then, calculate the moles using the molar mass:
Moles = Mass / molar mass = 77.03 g / 226.44 g/mol = 0.34 mol
1.2 For 7-octenyltrichlorosilane (C8H15Cl3Si):
- Calculate the grams of 7-octenyltrichlorosilane using the density and volume given:
Mass = density x volume = 1.07 g/mL x 2100 mL = 2247 g
- Then, calculate the moles using the molar mass:
Moles = Mass / molar mass = 2247 g / 245.65 g/mol = 9.15 mol
Step 2: Convert the moles to millimoles.
- Multiply the moles by 1000 to convert to millimoles:
For n-hexadecane: 0.34 mol x 1000 = 340 mmol
For 7-octenyltrichlorosilane: 9.15 mol x 1000 = 9150 mmol
Step 3: Calculate the total concentration in mM.
- Add the millimoles of both reagents together:
Total concentration = 340 mmol + 9150 mmol = 9490 mmol
Therefore, the concentration of the reagent in solution is 9490 mM.
Sure! I can help you with that.
To calculate the concentration in millimolar (mM) of the reagent in solution, we need to first calculate the number of moles of each substance present.
1. Start by calculating the number of moles of n-hexadecane:
- Given the volume (V) of n-hexadecane is 100.00 mL and the density (d) is 0.7703 g/mL.
- We can calculate the mass (m) of n-hexadecane using the formula: m = V * d.
- Plugging in the values, we get: m = 100.00 mL * 0.7703 g/mL = 77.03 g.
- Now, divide the mass (m) by the molecular weight (MW) of n-hexadecane to obtain the number of moles: n = m / MW.
- The molecular weight (MW) of n-hexadecane is given as 226.44 g/mol.
- Therefore, n = 77.03 g / 226.44 g/mol = 0.34 mol.
2. Next, calculate the number of moles of 7-octenyltrichlorosilane:
- Given the volume (V) of 7-octenyltrichlorosilane is 2.10 L and the density (d) is 1.07 g/mL.
- First, convert the volume from liters to milliliters: V = 2.10 L * 1000 mL/L = 2100 mL.
- Calculate the mass (m) of 7-octenyltrichlorosilane using the formula: m = V * d.
- Plugging in the values, we get: m = 2100 mL * 1.07 g/mL = 2247 g.
- Now, divide the mass (m) by the molecular weight (MW) of 7-octenyltrichlorosilane to obtain the number of moles: n = m / MW.
- The molecular weight (MW) of 7-octenyltrichlorosilane is given as 245.65 g/mol.
- Therefore, n = 2247 g / 245.65 g/mol = 9.14 mol.
3. Now that we have the number of moles for each substance, we can calculate the total concentration in moles per liter (mol/L):
- The total number of moles is the sum of moles of n-hexadecane and 7-octenyltrichlorosilane.
- Total moles = moles of n-hexadecane + moles of 7-octenyltrichlorosilane = 0.34 mol + 9.14 mol = 9.48 mol.
- The volume of the solution is given as 2.10 L for 7-octenyltrichlorosilane. Since n-hexadecane is negligible in comparison, we use 2.10 L.
- Therefore, the concentration in moles per liter (mol/L) is 9.48 mol / 2.10 L = 4.51 mol/L.
4. Finally, convert the concentration from moles per liter (mol/L) to millimolar (mM):
- There are 1000 millimoles (mmol) in 1 mole (mol).
- Multiply the concentration by 1000 to convert moles per liter (mol/L) to millimolar (mM).
- Concentration in mM = concentration in mol/L * 1000 = 4.51 mol/L * 1000 = 4510 mM.
Therefore, the concentration of the reagent in solution is 4510 mM.