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Chemistry

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a.) Caculate the energy of light emitted when an electron moves from n=2 to n=1 in the hydrogen atom.
b.) Caculate the energy of light emitted when an electron moves from n=4 to n=2 in the hydrogen atom.
c.) How many total different light energies can be emitted from an electron moving down from n=5?
I don't know the equation for a.) and b.), and I don't understand c.). Help please!

  • Chemistry -

    E= 2.180E-18(1/n^2(1) - 1/n^2(2))
    R = 1.09737E7
    n1 = 1 so n^2 = 1
    n2 = 2 so n^2 = 1/2^2 = 1/4

    For b the only difference is
    n1 = 2 so n^2 = 4
    n2 = 4 so n^2 = 16
    For c draw a diagram of energy levels that will look something like this.
    n = 5 -----------------
    n = 4 ----------------
    n = 3 ---------------
    n = 2 ---------------
    n = 1 --------------
    So an electron can move from
    5 to 4;
    5 to 3;
    5 to 2;
    5 to 1 and this results in 4 different energies being emitted.
    After the 5 to 4, then the 4 can do the same thing; i.e.,
    4 to 3;
    4 to 2;
    4 to 1; which results in 3 more energies being emitted.

    Then the electron that goes from 5 to 3 can separately do
    3 to 2; and
    3 to 1; resulting in two more and finally, the one at 2 can do
    2 to 1 resulting in 1 more. Add those together for the total. If I could draw a diagram on this site I could explain it much better.

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