Physics
posted by Luellen .
A boy's hand pushes a ball through a vertical distance of 1.45 m as he throws the ball straight upward. Once the ball leaves his hand it travels an additional 22 m (straight up) before returning to earth. Find the acceleration of the ball while it was in the boy's hand

You need to find the vertical velocity of the ball at launch.
The PE at the top=KE at launch
mg*22=1/2 m v^2
v= sqrt (2*g*22) m/s
now, considering just the period throwing
vf^2=vi^2+2ad
vf=above
vi=0
d=1.45m
solve for a