Chemistry

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if the H+ in acid mine drainage is 6.3 x 10^-5 mol/L, the pH of the drainage water is ___.

It would require ___ gal of 0.1 M
Ca(OH)2 (2 is a subscrip) to neutralize the proton acidity in 1000 gal of such drainage water.

  • Chemistry -

    pH = -log(H^+) = -log 6.3E-5 = ?

    Ca(OH)2 + 2H^+ ==> 2H2O + Ca^2+
    Convert 1000 gallons to L.
    Then L x 6.3E-5 mol/L = mol H^+.
    Mols Ca(OH)2 = 1/2 that (from the coefficients in the equation).
    M Ca(OH)2 = mols Ca(OH)2/L Ca(OH)2. Yo know M and mols; solve for L and convert that to gallons Ca(OH)2.

  • Chemistry -

    9809237

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