a point charge of 3.00*10^-6C is 12.o cm distance from a second charge of -1.50*10^-6 c. Calculate the magnitude of the force on each charge?

F=k•q₁•q₁/r²,

where
k =9•10⁹ N•m²/C²

To calculate the magnitude of the force on each charge, we can use Coulomb's Law, which states that the magnitude of the force between two point charges is given by the equation:

F = (k * |q1 * q2|) / r^2

Where:
- F is the magnitude of the force between the charges
- k is Coulomb's constant (9.0 * 10^9 Nm^2/C^2)
- |q1| and |q2| are the magnitudes of the charges
- r is the distance between the charges

Let's plug in the given values:

For the first charge:
- Magnitude of charge, q1 = 3.00 * 10^(-6) C
- Distance, r = 12.0 cm = 0.12 m (converted to meters)

For the second charge:
- Magnitude of charge, q2 = -1.50 * 10^(-6) C
- Distance, r = 0.12 m (same distance as the first charge)

Now, let's calculate the magnitude of the forces on each charge:

For the first charge:
F1 = (k * |q1 * q2|) / r^2
= (9.0 * 10^9 Nm^2/C^2 * |3.00 * 10^(-6) C * (-1.50 * 10^(-6) C)|) / (0.12 m)^2

Simplifying:
F1 = (9.0 * 10^9 Nm^2/C^2 * 4.5 * 10^(-12) C^2) / (0.0144 m^2)

Now, let's calculate the value:
F1 ≈ 2.8125 N

For the second charge:
F2 = (k * |q1 * q2|) / r^2
= (9.0 * 10^9 Nm^2/C^2 * |3.00 * 10^(-6) C * (-1.50 * 10^(-6) C)|) / (0.12 m)^2

Simplifying:
F2 = (9.0 * 10^9 Nm^2/C^2 * 4.5 * 10^(-12) C^2) / (0.0144 m^2)

Now, let's calculate the value:
F2 ≈ 2.8125 N

Therefore, the magnitude of the force on each charge is approximately 2.8125 Newtons.