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biochemistry

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Calculate the pH of the resultant solution of mixing together two solutions of 2 L of 1.0 M acetic acid, 0.5 L of 1.0 M sodium acetate and then adding 8 g of solid NaOH (MW = 40.0 g/mole).

  • biochemistry -

    Find starting # of moles of acid & base
    (2L)(1M) = 2 moles HA
    (.5L)(1M)= .5 moles A

    Add 8 g NaOH
    Convert grams to mole
    8g (1mol/40g) = .2 moles NaOH

    Find resulting # of moles
    2 mol - .2 mol = 1.8 mol HA
    .5 mol + .2 mol = .7 mol A

    Use Henderson–Hasselbalch equation to find pH. pKa of acetic acid is 4.77

    pH = pKa + log (A/HA)
    pH = 4.77 + log (.7/1.8)
    pH = 4.36

    Your answer is 4.36!

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