Math

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Find three consecutive intergers such that the product of the first and the second is two more than three times the third.

  • Math -

    suppose no are
    x, x+1, x+2

    Equal to condition

    {(x)*(x+1)}=3(x+2)+2
    -> x^2+x =3x+6+2
    -> x^2-2x-8=0
    -> x= 4 and -2

    so no are 4, 5 and 6

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