Find three consecutive intergers such that the product of the first and the second is two more than three times the third.
suppose no are
x, x+1, x+2
Equal to condition
{(x)*(x+1)}=3(x+2)+2
-> x^2+x =3x+6+2
-> x^2-2x-8=0
-> x= 4 and -2
so no are 4, 5 and 6