trig
posted by Deb .
An aircraft maintains a speed of 500 miles per hour in a southwestern direction. The velocity of the jet stream is constant 50 miles per hour from the west. Find the resultant vector, the speed, and actual direction of the aircraft.

R = 500mi/h @ 225o + 50mi/h @ 0o
X = 500*cos225 + 50 = 303.6/303.6 mi/h.
Y = 500*sin225 = 353.6 mi/h.
tanAr = Y/X = 353.6/303.6 = 49.35o =
Reference Angle.
A = 49.35 + 180 = 229.35o,CCW = 40.65o
West of South = Direction.
V = X/cosA = 303.6/cos229.35=466 mi/h.
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