What volume would be occupied at 0°C and 1 atm by 3 mol CO₂(g)?
I just might need someone to help me work this out, I would greatly appreciate it! I don't understand this chemistry problem.
You have 3 mols CO2 gas at 0C and 1 atm? What's the volume. Use PV = nRT.
P = pressure in atm
V = volume in L
n = mols
R = universal gas constant = 0.08206 L*atm/mol*K
T = temperature in kelvin. C + 273 = K.
To find the volume occupied by 3 mol of carbon dioxide (CO₂) gas at 0°C and 1 atm pressure, we can use the ideal gas law equation. The ideal gas law is given by:
PV = nRT
Where:
P is the pressure (in atm)
V is the volume (in liters)
n is the number of moles of the gas
R is the ideal gas constant (0.0821 L·atm/mol·K)
T is the temperature (in Kelvin)
First, convert the temperature from degrees Celsius to Kelvin by adding 273.15:
T = 0°C + 273.15 = 273.15 K
Next, substitute the known values into the ideal gas law equation:
1 atm * V = 3 mol * 0.0821 L·atm/mol·K * 273.15 K
Now, solve the equation:
V = (3 mol * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm
V = 66.21 L.
Therefore, the volume occupied by 3 mol of CO₂ gas at 0°C and 1 atm pressure is 66.21 liters.