Calculus
posted by Lisa .
In these complex exponential problems, solve for x:
1)e^(i*pi) + 2e^(i*pi/4)=?
2)3+3=3i*sqrt(3)=xe^(i*pi/3)
MY attempt:
I'm not really sure of what they are asking.
For the 1st one I used the e^ix=cos(x)+i*sin(x)
and got 1+sqrt(2) +sqrt(2)i
2) I solved for x and fot (3+3i*sqrt(3))/(1/2+i*sqrt(3)/2)

your 1st answer is correct
#2.
x(1/2 + √3/2 i) = 3+3i√3
x = (3+3√3 i))/[1/2 (1+√3 i)]
now rationalize by multiplying by conjugate
x = 3(1+√3 i)* 2(1√3 i)/(13)
x = 3(1+√3 i))(1√3 i)
x = 3(13)
x = 6
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