College Algebra
posted by Kristen .
I need some help with a few problems. They are multiple choice but need a breakdown on how I can work the problems. Thanks for your help!
1. Factor the trinomial completely. 10x^2 + 11x6
a. (2x+3)(5x2)
b. (2x3)(5x+2)
c. (10x+3)(x2)
d. (2x+1)(5x6)
2. Compute as indicated. Write answers in lowest terms. 9/2s+9/4s^2
a. 9s+9/4s^2
b. 27/2s
c. 18s+9/4s^2
d. 27/4s^2
3. Simplify the expression, assuming that the variable can represent any real number (8a^3/27)^4/3
a.  16a^4/81
b.  81/16a^4
c. 16a^4/81
d. 81/16a^4
4. Use the properties of exponents to simplify the expression. Write the answer using positive exponents only.. (a*b^4/c^7)^3
a. ab^12/c^21
b. b^12/a^3c^21
c. b^12c^7/a^3
d. ab^12c^7
5. Reduce to lowest terms x3/3x
a. 1
b. 1
c. x/3+3/x
d. x/33/x

1.10x^2+15x4x6 b should be split in such
a way that the product is equal to ac and the sum should be equal to b.
5x(2x+3)2(2x+3)
(2x+3)(5x2)
a
2.Find the LCM
(18s+9)/4s^2
c
3.[(2a/3)^3]^4/3
both 3 s get cancelled and we have 16a^4/81
c
4. Problem is not clear regarding powers and signs.
5.Take out minus sign from Numeratorand we will have 1 while everything gets cancelled 
5, Doesn't x3=(3x) ?
4. look at the a term a^3 has to appear in the answer. No answer is correct. Now if the problem is ((ab)^4)c^7)^3, then you have to have a^12 or 1/a^12. Again, no answer is correct.
3. what is cubrt(8a^3/27) ? now raise that to the 4th power (square it twice).
2. lowest term is 9s/2 (1+s2)
1. Let x=1. compute the trinomial. Now mentally check each answer with x=1. Which is the same?