4(7+a)-3=

10+3(1+p)=
6(b-4)=

To solve these equations, we need to follow the rules of algebra. Let's go through each equation step by step:

1) 4(7 + a) - 3 = 0
First, apply the distributive property by multiplying 4 with each term inside the parentheses.
4 * 7 + 4 * a - 3 = 0
28 + 4a - 3 = 0

Combine like terms:
25 + 4a = 0

Now, isolate the variable 'a' by moving the constant term to the other side of the equation:
25 + 4a - 25 = 0 - 25
4a = -25

Divide both sides of the equation by 4 to solve for 'a':
4a/4 = -25/4
a = -25/4

2) 10 + 3(1 + p) = 0
Again, apply the distributive property by multiplying 3 with each term inside the parentheses.
10 + 3 * 1 + 3 * p = 0
10 + 3 + 3p = 0

Combine like terms:
13 + 3p = 0

Isolate the variable 'p' by moving the constant term to the other side:
13 + 3p - 13 = 0 - 13
3p = -13

Divide both sides of the equation by 3 to solve for 'p':
3p/3 = -13/3
p = -13/3

3) 6(b - 4) = 0
Start by applying the distributive property:
6 * b - 6 * 4 = 0
6b - 24 = 0

Now, isolate the variable 'b':
6b - 24 + 24 = 0 + 24
6b = 24

Divide both sides of the equation by 6 to solve for 'b':
6b/6 = 24/6
b = 4

So, the solutions for the given equations are:
a = -25/4
p = -13/3
b = 4