Trig
posted by Anonymous .
log base b 64  log base b 16 = log base 4 16
solve for the variable..
i got to the part as far as:
(log 4/log b) = 2
now i m stuck at how i can isolate the b. plz help!

look at your right side
isn't log_{4} 16 = 2 ???
so you have:
log_{b} 64  log_{b}16 = 2
log_{b}(64/16) = 2
log_{b} 4 = 2
or
b^2 = 4
b = 2
from your:
log4/logb = 2
crossmultiply
log4 = 2logb
log4 = log b^2
then 4 = b^2
b = 2 , just like above 
log b (4) = 2
b^log b( 4) = 4
so b^logb(4) = b^2
so
b^2 = 4
b = 2 
Ohh alright! Thank you :)
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