a small conducted sphere is attached to the end of an insulating rod .it carries a charge of +5.0*10-9 C. the plates ,which are 4.0 cm apart, are connected to a 50 000 V supply.
Calculate
a)the magnitude of the electric field strenghen between the plates
b)the magnitude of the force on the sphere ,treated as a point charge of +5.0*10-9
Sure! Let's break it down step by step:
a) To calculate the magnitude of the electric field strength between the plates, we can use the formula E = V/d, where E is the electric field strength, V is the voltage, and d is the distance between the plates.
Given that the voltage is 50,000 V and the distance between the plates is 4.0 cm (which we will convert to meters), we can calculate the electric field strength as follows:
E = V/d
E = 50,000 V / (4.0 cm * 0.01 m/cm)
E = 50,000 V / 0.04 m
E = 1,250,000 V/m
Therefore, the magnitude of the electric field strength between the plates is 1,250,000 V/m.
b) To calculate the magnitude of the force on the sphere, we can use the formula F = qE, where F is the force, q is the charge on the sphere, and E is the electric field strength.
Given that the charge on the sphere is +5.0 * 10^-9 C and the electric field strength is 1,250,000 V/m (as calculated in part a), we can calculate the magnitude of the force as follows:
F = qE
F = (+5.0 * 10^-9 C) * (1,250,000 V/m)
F = 6.25 * 10^-3 N
Therefore, the magnitude of the force on the sphere is 6.25 * 10^-3 N.
To calculate the magnitude of the electric field strength between the plates, we can use the formula:
E = V/d
where E is the electric field strength, V is the voltage, and d is the distance between the plates.
a) Given:
V = 50,000 V
d = 4.0 cm = 0.04 m
Substituting these values into the formula, we get:
E = (50,000 V) / (0.04 m) = 1,250,000 V/m
Therefore, the magnitude of the electric field strength between the plates is 1,250,000 V/m.
To calculate the magnitude of the force on the sphere, we can use the formula:
F = q * E
where F is the force, q is the charge, and E is the electric field strength.
b) Given:
q = +5.0 * 10^-9 C
E = 1,250,000 V/m
Substituting these values into the formula, we get:
F = (+5.0 * 10^-9 C) * (1,250,000 V/m)
= 6.25 * 10^-3 N
Therefore, the magnitude of the force on the sphere is 6.25 * 10^-3 N.