Andrea caught seven more fish than Micah. Micah caught twice as many as Peter. If they caught a total of 37 fish, how may did each catch?
peter=x
micah=2x
andrea=2x+7
x+2x+2x+7=37
5x+7=37
5x=30
x=6
peter=6
micah=12
andrea=19
To solve this problem, we can use a system of equations. Let's assign variables to represent the number of fish each person caught.
Let's say the number of fish Peter caught is P.
Accordingly, Micah caught twice as many as Peter, so Micah caught 2P fish.
Andrea caught seven more fish than Micah, so Andrea caught 2P + 7 fish.
Now we can set up the equation based on the total number of fish they caught: P + 2P + (2P + 7) = 37.
Simplifying the equation, we get:
5P + 7 = 37
To isolate the variable, we subtract 7 from both sides:
5P = 30
Dividing both sides by 5, we find:
P = 6
So, Peter caught 6 fish.
Micah caught twice as many, which is 2 * 6 = 12 fish.
Andrea caught seven more than Micah, which is 12 + 7 = 19 fish.
In summary:
Peter caught 6 fish.
Micah caught 12 fish.
Andrea caught 19 fish.