An electron moving at a speed of 5 multiply by 10 raise to power six m/s was shot through a sheet of paper which is 2.1 multiply by 4cm thick.the electron emerges from the paper with a speed of 2 multiply by 10 raise to power six m/s,find the time taken by the electron to pass through the sheet.
vf - vi = 5*10^6 - 2*10^6 = 3*10^6
where vf is the final speed and vi is the initial speed.
Assuming a constant deceleration, the electron passes through 2.1 multiply 4cm = 8.4 cm of paper.
8.4 = 1/2*a*t^2
deltav = 3*10^6 = a*t
where a is the acceleration, t is the time. You have two equations with two unkowns (a and t). Use algebra to solve for t, the time taken by the electron to pass through the sheet.
To find the time taken by the electron to pass through the sheet, we can use the formula:
Time taken = Distance / Speed
First, we need to find the distance the electron traveled through the sheet. Since the sheet has a thickness of 2.1 cm, we need to convert it to meters.
1 cm = 0.01 m
Thus, the thickness of the sheet in meters would be:
2.1 cm * 0.01 m/cm = 0.021 m
Now we can calculate the distance traveled by the electron:
Distance = 0.021 m
The initial speed of the electron is 5 x 10^6 m/s, and the speed after passing through the sheet is 2 x 10^6 m/s.
Using the formula for time taken, we can substitute the known values:
Time taken = Distance / Speed
Time taken = 0.021 m / (5 x 10^6 m/s - 2 x 10^6 m/s)
Simplifying the equation gives us:
Time taken = 0.021 m / 3 x 10^6 m/s
Finally, the time taken by the electron to pass through the sheet is:
Time taken = 7 x 10^-9 s