math
posted by gary .
1. x=3y2/4,what is the value of y in terms of x ?
2. x=y^3/3y^2+y/2,what is the value of y in terms of x ?

1. I think you meant:
x = (3y2)/4
if so, then
.... times 4
4x = 3y  2
4x + 2 = 3y
y = (4x+2)/3
2. I will take your question the way you typed it except I think your denominator for the first fraction is probably 3y^2, so it needs brackets
x = (1/3) y + y/2
times 6
6x = 2y + 3y
6x = 5y
y = 6x/5 
thank you, Reiny
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