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A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 5.908×10−10 m. Determine the frequency (in hz) of the interacting photon.

  • chemistry -

    E = P^2/2Me + E(first ionization)

    P= h / BroglieWavelength

    E(first ionization)=21.7*10^-19

    Me= 9.1*10^-31

    h= 6.626*10^-34

    frecuency(hz)= E / h

  • chemistry -

    Chemgam, can you please clarify what is (P^2)? do you mean (Momentum) X (Momentum)

    I made it like this, but it gave me wrong answer

  • chemistry -

    P = h/ BroglieWavelength

    Like he says. It is correct

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