mass of evaporating dish 22.34
mass of evaporating dish +hydrate 24.64
mass of evaporating dish +anhydrous salt 23.85
CuS04XH2O=CuSO4+XH2O
1.determine the mass of the water lost
2.determine the number of moles of the water lost
See your other post under may. You get quicker answers if you use the same screen name.
To determine the mass of the water lost and the number of moles of water lost, we need to calculate the initial mass of water in the hydrate and the final mass of water remaining in the anhydrous salt.
1. Calculate the mass of water lost:
Mass of evaporating dish + hydrate = 24.64 g
Mass of evaporating dish + anhydrous salt = 23.85 g
To find the mass of water lost, subtract the final mass from the initial mass:
Mass of water lost = (Mass of evaporating dish + hydrate) - (Mass of evaporating dish + anhydrous salt)
Mass of water lost = 24.64 g - 23.85 g
Mass of water lost = 0.79 g
Therefore, the mass of water lost is 0.79 grams.
2. Determine the number of moles of water lost:
To determine the number of moles, we need to use the molar mass of water (H2O), which is 18 g/mol.
Number of moles of water lost = Mass of water lost / Molar mass of water
Number of moles of water lost = 0.79 g / 18 g/mol
Number of moles of water lost ≈ 0.0439 mol
Therefore, the number of moles of water lost is approximately 0.0439 moles.