posted by Anonymous .
At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 593.0 kg of PbS and 890 kg of PbO.
one way. figure the percent lead in PbS, and the percent in PbO, then add the mass of lead in each.
2PbO+PbS>>3Pb + SO2
calculate the moles of PbO in 890kg. then the moles of pb is 3/2 times that. Reconvert that to mass.