Post a New Question

Chemistry

posted by .

The solubility of bismuth iodide (BiI3) in water is 3.691 x 10-3 M. Calculate the value of the solubility product. The dissolution products are Bi3+(aq) and I−(aq)

  • Chemistry -

    I worked this above for Bi2S3. Same procedure.

  • Chemistry -

    27(3.691*10^-3)^4

  • Chemistry -

    5.043*10^-7

  • Chemistry -

    can you explain me how to do it please?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question