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A 2kg and a 4kg hang freely at opposite ends of a light inextensible string which passes over a small and light pulley fixed to a rigid support calculate the acceleration of the system

  • physics -

    m₁a=m₁g -T
    m₂a=m₂g-T
    a(m₁-m₂)=g(m₁+m₂)
    a =g(m₁+m₂)/(m₁-m₂)= ...

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    3.3

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