Algebra 2
posted by Bart .
I know the answer to this problem is 1. I found that by substituting for x and seeing if it worked. How should I do it the correct way?
(x/(3x+6))(x+1/3x6)=(1/(x^2)4)

first, use enough parens to be correct:
(x/(3x+6))(x+1)/(3x6)=(1/(x^2)4)
factor out the 1/3 on the left side, and factor the right side
1/3 (x/(x+2)  (x+1)/(x2)) = 1/((x+2)(x2))
now put LS over a common denominator
1/3 (x(x2)  (x+1)(x+2))/((x2)(x+2)) = 1/((x+2)(x2))
multiply through by 3(x2)(x+2)
x(x2)  (x+1)(x+2) = 3
x^2  2x  x^2  3x  2 = 3
5x  2 = 3
5x = 5
x = 1 
Thank you for your help. I still need some more explaining. I understand factoring out the 1/3 on the left hand side. I also understand factoring the denominator on the right hand side. After that I have trouble. Could you please show it to me again, but this time with more steps shown?

If you are ok to here:
1/3 (x/(x+2)  (x+1)/(x2)) = 1/((x+2)(x2))
Think of it as something like
1/3 (3/5  4/7) = 1/(35)
To clear the fractions, multiply by the LCD of them all: 3*5*7 = 35
In our case, 3(x+2)(x2)
1/3 x/(x+2) * 3*(x2)(x+2) > x(x2)
the other factors cancel out. Do that for all three terms of the equation and you get to the next step, which is much easier to read:
x(x2)  (x+1)(x+2) = 3
and from there it should be clear. That help?