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Line segment AB intersects line segment ED in the middle at the point C

If DC=6+x and CE=2x+1, what is the lenth of ED?
A. 5
B. 11
C. 22
D. 10

Answer: C

Line segment AB intersects line segment ED in the middle at the point C

If DC=6+x and CE=2x+1, find the value of x
A. 10
B. 5
C. 22
D. 11

Answer: a.

To find the length of ED, we need to add the length of DC and CE.

Given that DC = 6 + x and CE = 2x + 1, we can add them together:

DC + CE = (6 + x) + (2x + 1)
= 6 + x + 2x + 1
= 3x + 7

Now, we need to find the length of ED, which is the sum of DC and CE:

ED = DC + CE
= 3x + 7

To find the value of x, we can set the equation 3x + 7 equal to the length of ED:

3x + 7 = ED

Since we are given that the length of ED is equal to 22 (from the previous answer), we can substitute 22 into the equation:

3x + 7 = 22

Now, we can solve for x:

3x + 7 = 22
3x = 22 - 7
3x = 15
x = 15/3
x = 5

Therefore, the value of x is 5.

To summarize:
- The length of ED is represented by the equation 3x + 7.
- The value of x is found to be 5.

So, the correct answer is B.