Equation for b(c+4)=4c-18
To solve the equation b(c+4) = 4c - 18, we can use some basic algebraic principles.
Step 1: Distribute the 'b' on the left side of the equation, b(c+4). This means multiplying 'b' by both 'c' and '4', resulting in bc + 4b.
The equation now becomes bc + 4b = 4c - 18.
Step 2: Next, we want to collect all the terms that contain 'c' on one side of the equation. To do this, we'll move the term '4c' to the left side by subtracting 4c from both sides of the equation.
bc + 4b - 4c = 4c - 18 - 4c.
Simplifying this gives us bc + 4b - 4c = -18.
Step 3: Now, we want to collect all the constant terms on the other side of the equation. To do this, we'll move the term '-18' to the right side by adding 18 to both sides of the equation.
bc + 4b - 4c + 18 = -18 + 18.
This simplifies to bc + 4b - 4c + 18 = 0.
Step 4: The next step is to factor out any common terms if possible. Although there are no common factors in this equation, you should always look for this step in other equations.
Step 5: To simplify the equation further, you can rearrange the terms in a different order. It won't affect the solution.
bc - 4c + 4b + 18 = 0.
So, the simplified equation is bc - 4c + 4b + 18 = 0.
Now, you have the equation in standard form.