chemistry
posted by jessica .
If 8 cm3 of 9.9 mol m3 Fe(NO3)3 are mixed with 10 cm3 of 1.0 mol m3 KSCN solution in a 20 cm3 volumetric flask and water is added to bring the total volume up to 20 cm3, what is the concentration of the Fe3+ ions (in mol m3)?

You know Fe^3+ forms the FeSCN^2+ complex. What are the units for cc x m^3? millimols/m^3?
8 x 9.9 = 79.2
10 x 1 = 10
.........Fe^3+ + SCN^ ==> FeSCN^2+
I.......79.2.....10.........0
C......10......10........10
E.......69.2......0........10
Keq for this reaction is relatively large; we assume all of the "free" Fe^3+ is due to that which has not reacted. Thus the concn Fe^3+ is
69.2 mmols x (8 cc/20 cc) = ? mol/m^3
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