math--please check

posted by .

Change the logarithmic equation to an equivalent equation involving an exponent.

log8^64=2
**note that the 8 should be lower than the g**

8^(log64)=8^2
64=8^2

is this correct

  • math--please check -

    You are correct
    you could just use the definition.

    I used to tell my students to "memorize" the following pattern

    2^3 = 8 <-------> log2 8 = 3

    that way you can tell what goes where.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Calculus

    How do I rewrite log4 1=0 as an equivalent exponential equation?
  2. Calculus

    I am unsure of how to take the derivative of this equation. It may be the exponents that are giving me trouble but I'm not sure exactly. Find the equation of the tangent line to the curve 4e^xy = 2x + y at point (0,4). On the left …
  3. Math - changing logarithmic expression

    Change the logarithmic expression to an equivalent expression involving an exponent. Log1/5(1/625) = C
  4. algebra

    change the logarithmic expression to an equivalent expression involving an exponent. 4^16=x log (base4)16=x is it x=e^2?
  5. alg

    change the logarithmic expression to an equivalent expression involving an exponent. 4^16=x log (base4)16=x is it x=e^2?
  6. pre-calculus

    Change the logarithmic expression to an equivalent expression involving an exponent. Log7343=x the 7 should drop down lower than the 343.
  7. college algebra, Please help!!

    change the exponential expression to an equivalent expression involving a logarithm. 1.9=a^6 a=1.1129 is this the correct logarithmic expression?
  8. math

    chane the logarithmic expression to an equivalent expression involving an exponent log416=x **the 4 is supposed to be dropedd down lower by the g.**
  9. prcalculus

    change the logarithmic expression to an equivalent expression involving an exponent. log416=x
  10. Logarithmic Function

    Could you please verify and calculate the following logarithmic equation: y = 2log_2(2)(x+2)-4 , in which x=2. So the equation would become: y = 2log_2(2)(2+2)-4 Solving... y = 2log_2(2)(4)-4 y = 2log_2(8)-4 y = 2(3)-4 y = 6-4 y = …

More Similar Questions