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determine the molarity of the following solution 31 g MgF2 in 55ml H20

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    mols = grams/molar mass.
    Then M = mols/L soln.
    Technically this problem can't be solved because the definition of M is mols/L solution. You have added MgF2 to 55 mL H2O. I'm sure your prof expects you to use 0.055 L BUT 31 g MgF2 in 55 mL H2O gives more than 55 mL of solution.

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