Post a New Question


posted by .

How many grams of oxygen are needed to burn 22.8 grams of C8H18?
80.0 g
240. g
40.0 g
20.0 g
120. g

  • chemistry -

    depends on the reaction. Is it

    2C8H18 + 9O2 = 16C + 18H2O ?

    If so, since you have 22.8/114 = 0.2 moles of C8H18, you will need 9/2*.2 = 0.9 moles of O2, or 28.8g

    nope. So, Fix the reaction and adjust the moles of O2 needed.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question