Science math
posted by Joshua .
Suppose a laboratory has a 38 g sample of polonium210. The halflife of polonium210 is about 138 days. How many halflives of polonium210 occur in 1104 days? How much polonium is in the sample 1104 days later?

1104/138 = 8 halflives
after 8 halflives, 1/256 remains, or 0.148g 
How many halflives of polonium210 occur in 1104 days? 1104/138 = 8.0 halflives
How much polonium is in the sample 1104 days later? 38 g * (1/2)^8 = 0.148 g 
Thank you both very much.

8; 2,622 g

8; 0.11

8';0.148
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