maths
posted by faizel .
Given is a quadrilateral ABCD,diagonals AC and BDare such that AO=BO=CO=DO=3cm,where Ois point of intersection of AC and BD then quadrilateral ABCD is a rectangle State true or false with reason

True.
Triangle ABO is congruent to triangle CDO.(Sideangleside equality) Triangle BCO is congruent to triangle DAO (sideangleside equality)
Opposite pairs of sides of the quadrilateral are equal in length (due to triangle congruency).
Angles A, B, C and D are right angles.(symmetry requirement)