A force of 3.0 newtons applied to an object produces a change in velocity of 12 meters per second in 0.40 second. the mass of the object is?
I am not sure how to solve this problem. Formula for momentum is
p= mass times velocity
impulse (J) = Fnet times time in seconds
Since F = M*a, use
M = F/a
The acceleration (a) is (V2-V1)/t
= 12/0.4 = 30 m/s^2
M = 3.0/30 = 0.10 kg.
Oh. That was quite straight forward. Thank you.
To solve this problem, you can use the formula for impulse:
Impulse (J) = Force (F) × time (t)
Given that the force is 3.0 newtons and the time is 0.40 seconds, you can calculate the impulse:
J = 3.0 N × 0.40 s
J = 1.2 N·s
The impulse is also equal to the change in momentum (Δp) of the object:
Δp = 1.2 N·s
Since the change in velocity (Δv) is given as 12 meters per second, you can use the formula for momentum to find the mass:
Δp = mass (m) × Δv
1.2 N·s = m × 12 m/s
To solve for the mass, divide both sides of the equation by 12 m/s:
m = 1.2 N·s / 12 m/s
m = 0.1 kg
Therefore, the mass of the object is 0.1 kilograms.
To solve this problem, we'll use the formula for impulse. Impulse (J) is equal to the product of the net force (Fnet) applied to an object and the time interval (Δt) during which the force is applied.
Impulse (J) = Fnet * Δt
We know the impulse (J) is equal to the change in momentum (Δp) of the object, which is given by the equation:
Δp = m * Δv
where m is the mass of the object and Δv is the change in velocity.
In this case, we are given that the net force (Fnet) applied to the object is 3.0 newtons, the change in velocity (Δv) is 12 meters per second, and the time interval (Δt) is 0.40 seconds.
Using the formula for impulse, we can write:
J = Fnet * Δt
Δp = m * Δv
Since impulse (J) is equal to the change in momentum (Δp), we can set the two equations equal to each other:
Fnet * Δt = m * Δv
We can rearrange this equation to solve for the mass (m):
m = (Fnet * Δt) / Δv
Plugging in the given values, we get:
m = (3.0 N * 0.40 s) / 12 m/s
m = 0.10 kg
Therefore, the mass of the object is 0.10 kilograms.