For reduction of 1,4 dinitrobenzene when doing the equation I add h20 at end then count how many H's on right side which is 10 as 1,4diaminobenzene has 8, then on left there are 4H's on 1,4 dinitrobenzene. so that means you need 6(H). But how come in the actual equation there are sudddenly 4H20's
In the reduction of 1,4-dinitrobenzene to 1,4-diaminobenzene, water (H2O) is typically used as a reagent to provide the necessary hydrogen atoms for the reduction process. The balanced chemical equation for this reaction would look like this:
C6H4N2O4 + 6H2O → C6H8N2 + 4H2O
Let's break it down step by step to understand why there are four H2O molecules on the left side of the equation:
1. Begin with the molecular formula of 1,4-dinitrobenzene: C6H4N2O4.
2. Since you want to reduce the nitro groups (NO2) in 1,4-dinitrobenzene to amino groups (NH2) in 1,4-diaminobenzene, you need to provide hydrogen (H) atoms to replace the oxygen (O) atoms in the nitro groups.
3. Each nitro group (NO2) contains two oxygen atoms, so you need six hydrogen atoms to replace them (3 hydrogen atoms per oxygen atom).
4. This is why we need six H2O molecules (each H2O molecule provides two hydrogen atoms) on the right side of the equation.
5. By adding these six hydrogen atoms to 1,4-dinitrobenzene, the nitro groups are reduced to amino groups, and you get 1,4-diaminobenzene (C6H8N2) as the product.
6. On the left side of the equation, there are four H2O molecules present as reactants because water is commonly used as a solvent in this reaction.
So, the presence of four H2O molecules on the left side of the balanced equation allows for the provision of the necessary hydrogen atoms to reduce 1,4-dinitrobenzene to 1,4-diaminobenzene.