algebra
posted by anonymous .
what is the solution of the system of equations.
2x+2y+3z=6
3x+5y+4z=3
2x+3y+4z=10

(x,y,z) = (5,4,8)

is there away to show your work

sure. One way is to do elimination by adding and subtracting multiples of one equation from another.
subtract 2*second from 3*first:
6x+6y+9z = 18
6x+10y+8z = 6

4y + z = 24
subtract first from third
y  z = 4
now add those two to get
5y = 20
y=4
so, z=8 and x=5
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