calculus

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integrate it by integrating factor

(cos^3x)dy/dx +ycosx=sinx

  • calculus -

    Hmmm. rearrange things a bit to get

    y' + sec^2 x y = tan x sec^2 x
    that is
    y' + P(x)y = Q(x)

    integrating factor is thus e^∫sec^2 x dx = e^(tan x)

    now plug and chug

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