PreCal
posted by phyllys .
Solve the following logarithmic equation. Exact words only:
log 3(x+4) = 2+log3(x20)
the 3 in the part of log (3)should be lower just didn't know how to type it in here

log3 (x+4)  log3 (x20) = 2 , where clearly x > 20
log3 ( (x+4)/(x20) ) = 2
(x+4)/(x20) = 3^2 = 9
9x  180 = x+4
8x = 184
x = 23
check:
LS = log3 27 = 3
RS = 2 + log3 3
= 2 + 1 = 3 = LS
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