calculus
posted by Lisa .
Find the distance d(P1,P2)between the points P1 and P2.
P1=(5,2)
P2=(2,1)
d(P1,P2)=?
*all the 1's and 2's are to be lower down.* Please show work

The distance between the X coordinates is 2 minus 5 = 7. The distance between the Y coordinates is 2 minus 1 = 1. Those two distances are the base and height of a rightangled triangle, so to get the hypoteneuse, use Pythagoras: that gives you that the distance is the square root of (7*7 + 1*1) = sqrt(50) = roughly 7.071. I don't know where the calculus comes in, though.
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