calculus
posted by NayNay .
solve the logarithmic equation. Be sure to reject any value of x that is not in the domain.
In square root x+7=1
x= ?
What is the decimal approximation to the solution?
x= ?
Respond to this Question
Similar Questions

Logs.
Can you please help me with the following log. problems? 
algebra homework
please check my answers. Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the original logarithmic expressions. Give the exact answer. ln sqrt x+6 = 9 i got {e^96} log (x + 4) = log (5x  5) … 
Calculus
Find the functions a) f o g, b) g o f, c) f o f, d) g o g, and their domains. f(x)= square root of x, g(x)= cube root of 1x These are my answers, but I am not sure about them and I only figured out one domain... that is the part that … 
precalculus
solve the following logarithmic equation. Be sure to reject any value of x that is not in thedomain of the orginal logarithmic expression. Give the exact answer. log3(x+8)=4 The three actually drops down a little below the g. Can someone … 
precalculus
solve the logarithmic equation. be sure to reject any value of x that is not in the domain of the orginal logarithmic expression. In square root of x+2=2 (If I try to make the square root sign it will not come out right so I wrote … 
precalculus
solve the following logarithmic equation. be sure to reject any value of x that is not in the domain of the original logarithmic expression. give the exact answer. then, use the calculator to obtain a decimal appromiation, correct … 
calculus
solve the following logarithmic equation. Be sure to reject any value of x that is not in the domain of orginal expression. then in the solution set round to two decimals places. Inx=8 I get e^8 But am having a hard time with rounding … 
calculus
solve the logarithmic equation. be sure to reject any value of x that is not in the domain of the orginal logarithmic expression. In square root x+7=2 what is the exact solution? 
calculus
solve the logarithmic equation. Be sure to reject any value of x that is not in the domain of the orginal logarithmic expression. In square root x+7=1 I get this far and then get stuck, can you help me? 
Algebra
Solve the logarithmic equation. Be sure to reject any value of x that is not in the domain of the original logarithmic expression. ln ã(x+4)=1 What is the exact solution?