Maths
posted by Shruti katiyar .
Three circles are placed on a plane in such a way that each circle just touches the other two each having a radius of 10 cm. Area of the region enclosed by them.

the circle centers form an equilateral triangle with side 10.
area of triangle is thus √3/4 10^2 = 25√3
each side of the triangle subtends an angle of π/3, and the segment formed has area 1/2 *25*(π/3√3/2) = 25/12 (2π3√3).
Subtract the area of the 3 segments from the triangle, leaving
25√3  25/4 (2π3√3) =~ 36.5
you can massage that if you want. 
oops  I used a diameter of 10 cm. Adjust accordingly.