An object is thrown vertically upward at 18m/s from a window and hits the

ground 1.6s later. What is the height of the window above the ground?(air

resistance is negligible)

Well, if we take out our trusty clown ob-jec-tion handling tool-kit and give it a spin, we can calculate the height of the window above the ground. So, let's dive in, shall we?

First, we need to find the time it takes for the object to reach the highest point of its trajectory. Since the object was thrown upwards at a velocity of 18m/s and then came back down to earth in a total of 1.6 seconds, we can divide that time by 2 to find the time it took for the object to reach its highest point. That would be 0.8 seconds.

Now, we can use the equation for free fall to find the height. The equation goes like this: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.

Plugging the numbers in, we get h = (1/2)(9.8 m/s^2)(0.8 s)^2, which gives us a height of approximately 3.94 meters.

So, according to my extremely scientific calculations, the height of the window above the ground is approximately 3.94 meters. Hope that helps, and let the comedic physics begin!

To solve this problem, we can use the equation for vertical displacement:

s = ut + (1/2)gt^2

where:
s = vertical displacement (height)
u = initial velocity (18 m/s)
t = time (1.6 s)
g = acceleration due to gravity (9.8 m/s^2)

Let's plug in the values:

s = (18 m/s)(1.6 s) + (1/2)(9.8 m/s^2)(1.6 s)^2

s = 28.8 m + (0.5)(9.8 m/s^2)(2.56 s^2)

s = 28.8 m + 12.704 m

s = 41.504 m

Therefore, the height of the window above the ground is 41.504 meters.

To find the height of the window above the ground, we can use the equations of motion for vertical motion.

The equation we will use is:
h = (vi * t) - (1/2 * g * t^2)

Where:
h is the height
vi is the initial velocity
t is the time
g is the acceleration due to gravity (9.8 m/s^2)

Given:
vi = 18 m/s (the initial velocity)
t = 1.6 s (the time taken to hit the ground)

We can substitute the values into the equation and solve for h:

h = (18 * 1.6) - (1/2 * 9.8 * 1.6^2)
h = 28.8 - (1/2 * 9.8 * 2.56)
h = 28.8 - (12.16)
h = 16.64 meters

Therefore, the height of the window above the ground is 16.64 meters.

Let h be the window height above ground.

At t = 1.6 seconds,

Elevation y = h + 18t -4.9t^2 = 0
so
h + 28.8 -12.54 = 0

h would be negative. It cannot hit the ground that soon if thrown upaward at that high speed. Recheck you numbers