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Two cylinders have the same volume. If the radius of cylinder I is 3 times the radius of cylinder II, then the height of cylinder II is how many times the height of cylinder I?
A. 12
B. 9
C. 6
D. 3

Please explain how, if possible.

  • Geometry -

    Cylinder 1 has nine times the base area of cylinder 2.
    Volume is (base area) x (height)
    For the volumes to be equal, cylinder 2 must have 9 times the height of cylinder 2.

  • Geometry -

    pi*r^2*h2 = pi*(3r)^2*h1.
    pi*r^2*h2 = pi*9r^2*h1
    Divide both sides by pi*r^2:
    h2 = 9*h1.

  • Geometry (typo correction) -

    For the volumes to be equal, cylinder 2 must have 9 times the height of cylinder 1

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