PreCal.
posted by phyllys .
Solve the following inequality . Write your solution in interval notations. x+3/x3<0.

PreCal. 
Steve
since (x+3)/(x3) = 1 + 6/(x3)
1 + 6/(x3) < 0
6/(x3) < 1
if (x3) > 0, that is, x > 3
6 < 3x
x < 3
no good, since we specified x > 3
If (x3) < 0, that is, x < 3
6 > 3x
x > 3
so, the solution is (3,3)
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