prove that
mean of cubes of first n natural numbers is [n(n+1)(n+1)]/4
by induction, you can show that
n
∑ k^3 = n^2 * (n+1)^2 / 4
k=1
now divide by n, and you're done.
mean of cubes of first n natural numbers is [n(n+1)(n+1)]/4
n
∑ k^3 = n^2 * (n+1)^2 / 4
k=1
now divide by n, and you're done.