Every year a man is paid Rs 500more than the previous year. If he receives Rs 17800 over four years, what was he paid on the first year
Let X = first year payment
X + (X+500) + (X+2*500) + (X+3*500) = 17800
4X + 3000 = 17800
4X = 14800
X = 3700
is there easier way to do for 10 years
To find out what he was paid in the first year, let's break down the problem:
Let the amount he was paid in the first year be 'x' rupees.
In the second year, he would be paid x + 500 rupees.
In the third year, he would be paid (x + 500) + 500 rupees = x + 1000 rupees.
In the fourth year, he would be paid (x + 1000) + 500 rupees = x + 1500 rupees.
Adding up the amounts over the four years, we have:
x + (x + 500) + (x + 1000) + (x + 1500) = 17800.
Simplifying the equation:
4x + 3500 = 17800.
Subtracting 3500 from both sides:
4x = 14300.
Dividing both sides by 4:
x = 3575.
Therefore, he was paid Rs 3575 in the first year.