If 50.0 g of benzene, C6H6, at 25.0 °C absorbs 2.71 kJ of energy in the form of heat, what is the final temperature of the benzene? The specific heat capacity of benzene is 1.72 J/g ⋅K.

q = 2710 J = mass bz x specific heat bz x (Tfinal-Tinitial)

Solve for specific heat bz.

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Well, let's do some clown math, shall we?

First, we need to calculate how much the temperature increases when 2.71 kJ of heat is absorbed by the 50.0 g of benzene.

We can use the equation:
q = m * c * ΔT
Where:
q is the heat absorbed (2.71 kJ = 2710 J)
m is the mass of benzene (50.0 g)
c is the specific heat capacity of benzene (1.72 J/g · K)
ΔT is the change in temperature that we want to find

Rearranging the equation to solve for ΔT, we have:
ΔT = q / (m * c)

Plug in the known values:
ΔT = 2710 J / (50.0 g * 1.72 J/g · K)

Calculating this gives us:
ΔT = 31.55 K (approximately)

Now, we need to find the final temperature by adding the change in temperature to the initial temperature of 25.0°C.

So, the final temperature is:
Final temperature = Initial temperature + ΔT
Final temperature = 25.0 °C + 31.55 K

And to make things simple (or rather, clown-like), we can just convert the change in temperature from Kelvin to Celsius:
Final temperature = 25.0 °C + 31.55 °C

Drumroll, please...

Final temperature = 56.55 °C

So, after absorbing 2.71 kJ of heat, the final temperature of the benzene is approximately 56.55 °C. Stay cool, benzene!

To find the final temperature of the benzene, we can use the equation for heat transfer:

Q = m × c × ΔT

where:
Q = heat transferred (in joules or J)
m = mass of the substance (in grams or g)
c = specific heat capacity of the substance (in J/g⋅K)
ΔT = change in temperature (in degrees Celsius or °C)

In this case, we are given:
Q = 2.71 kJ = 2.71 × 1000 J
m = 50.0 g
c = 1.72 J/g⋅K
ΔT = final temperature - initial temperature

We need to rearrange the equation to solve for ΔT:

ΔT = Q / (m × c)

Substituting the given values, we get:

ΔT = 2.71 × 1000 J / (50.0 g × 1.72 J/g⋅K)

Calculating this gives:

ΔT ≈ 31.512 K

Now, to find the final temperature, we need to add this change in temperature to the initial temperature:

Final temperature = Initial temperature + ΔT

The initial temperature is given as 25.0 °C, so:

Final temperature = 25.0 °C + 31.512 K

Converting the result to degrees Celsius:

Final temperature ≈ 56.512 °C