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I'm studying to take a math placement exam and it has been a long time since I've taken a math class. Can someone please give me a step to step solution of these:

8x/[2^(x-1)] Answer = 2^(2x+1)

(2^x)*[4^(x-1)] Answer = 2^(3x-2)

  • Math -

    x (2^3) 2^(-x+1)
    x (2^-x)( 16)
    16 x/2^x
    I bet you mean
    8^x [2^(-x+1)]
    2^3x [2^-x 2^1]

    2^x 2^(2x-2)

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