calculus
posted by Jimmycan someone please help .
form a polynomial with real coefficients have given degree and zeros.
degree 5, zeros 9, i; 8+i
please show work

calculus 
Steve
complex roots are in pairs, so we have
(x9)(x+i)(xi)(x(8+i))(x(8i))
(x9)(x^2+1)((x8)^2 + 1)
. . .
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