physics

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An object is thrown vertically upward such
that it has a speed of 56 m/s when it reaches
two thirds of its maximum height above the
launch point.
Find the maximum height h. The acceleration of gravity is 9.8 m/s
2
.
Answer in units of m

  • physics -

    At 2/3 of its maximum height, it has 1/3 of its initial kinetic energy left. That means it has 1/sqrt3 = 0.5773 of its initial velocity. The initial velocity must have been
    Vo = 56/0.5773 = 96.99 m/s.

    Max height is Vo^2/(2*g)
    = 480 m

  • physics -

    v.=56m/s
    v=0
    g=-10m/s2
    v2=V.2+2gyx
    0=3136-2.9.8.x
    19.6x=3136m
    x=160m
    1/3x=160m
    x=3.160=480m

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